Integrand size = 27, antiderivative size = 266 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {a x}{b^3}+\frac {2 a \left (2 a^2-3 b^2\right ) x}{b^5}+\frac {2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^5 d}-\frac {2 \left (a^2-b^2\right )^{3/2} \left (5 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^2 b^5 d}-\frac {\text {arctanh}(\cos (c+d x))}{a^2 d}+\frac {\cos (c+d x)}{b^2 d}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{b^4 d}-\frac {\cos ^3(c+d x)}{3 b^2 d}-\frac {a \cos (c+d x) \sin (c+d x)}{b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 d (a+b \sin (c+d x))} \]
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Time = 0.26 (sec) , antiderivative size = 266, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.407, Rules used = {2976, 3855, 2718, 2715, 8, 2713, 2743, 12, 2739, 632, 210} \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{b^5 d}-\frac {2 \left (a^2-b^2\right )^{3/2} \left (5 a^2+b^2\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a^2 b^5 d}-\frac {\text {arctanh}(\cos (c+d x))}{a^2 d}+\frac {2 a x \left (2 a^2-3 b^2\right )}{b^5}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{b^4 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 d (a+b \sin (c+d x))}-\frac {a \sin (c+d x) \cos (c+d x)}{b^3 d}+\frac {a x}{b^3}-\frac {\cos ^3(c+d x)}{3 b^2 d}+\frac {\cos (c+d x)}{b^2 d} \]
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Rule 8
Rule 12
Rule 210
Rule 632
Rule 2713
Rule 2715
Rule 2718
Rule 2739
Rule 2743
Rule 2976
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {2 \left (-2 a^3+3 a b^2\right )}{b^5}+\frac {\csc (c+d x)}{a^2}+\frac {3 \left (-a^2+b^2\right ) \sin (c+d x)}{b^4}+\frac {2 a \sin ^2(c+d x)}{b^3}-\frac {\sin ^3(c+d x)}{b^2}+\frac {\left (a^2-b^2\right )^3}{a b^5 (a+b \sin (c+d x))^2}-\frac {\left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )}{a^2 b^5 (a+b \sin (c+d x))}\right ) \, dx \\ & = \frac {2 a \left (2 a^2-3 b^2\right ) x}{b^5}+\frac {\int \csc (c+d x) \, dx}{a^2}+\frac {(2 a) \int \sin ^2(c+d x) \, dx}{b^3}-\frac {\int \sin ^3(c+d x) \, dx}{b^2}-\frac {\left (3 \left (a^2-b^2\right )\right ) \int \sin (c+d x) \, dx}{b^4}+\frac {\left (a^2-b^2\right )^3 \int \frac {1}{(a+b \sin (c+d x))^2} \, dx}{a b^5}-\frac {\left (\left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{a^2 b^5} \\ & = \frac {2 a \left (2 a^2-3 b^2\right ) x}{b^5}-\frac {\text {arctanh}(\cos (c+d x))}{a^2 d}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{b^4 d}-\frac {a \cos (c+d x) \sin (c+d x)}{b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 d (a+b \sin (c+d x))}+\frac {a \int 1 \, dx}{b^3}+\frac {\left (a^2-b^2\right )^2 \int \frac {a}{a+b \sin (c+d x)} \, dx}{a b^5}+\frac {\text {Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{b^2 d}-\frac {\left (2 \left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^2 b^5 d} \\ & = \frac {a x}{b^3}+\frac {2 a \left (2 a^2-3 b^2\right ) x}{b^5}-\frac {\text {arctanh}(\cos (c+d x))}{a^2 d}+\frac {\cos (c+d x)}{b^2 d}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{b^4 d}-\frac {\cos ^3(c+d x)}{3 b^2 d}-\frac {a \cos (c+d x) \sin (c+d x)}{b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 d (a+b \sin (c+d x))}+\frac {\left (a^2-b^2\right )^2 \int \frac {1}{a+b \sin (c+d x)} \, dx}{b^5}+\frac {\left (4 \left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^2 b^5 d} \\ & = \frac {a x}{b^3}+\frac {2 a \left (2 a^2-3 b^2\right ) x}{b^5}-\frac {2 \left (a^2-b^2\right )^{3/2} \left (5 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^2 b^5 d}-\frac {\text {arctanh}(\cos (c+d x))}{a^2 d}+\frac {\cos (c+d x)}{b^2 d}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{b^4 d}-\frac {\cos ^3(c+d x)}{3 b^2 d}-\frac {a \cos (c+d x) \sin (c+d x)}{b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 d (a+b \sin (c+d x))}+\frac {\left (2 \left (a^2-b^2\right )^2\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^5 d} \\ & = \frac {a x}{b^3}+\frac {2 a \left (2 a^2-3 b^2\right ) x}{b^5}-\frac {2 \left (a^2-b^2\right )^{3/2} \left (5 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^2 b^5 d}-\frac {\text {arctanh}(\cos (c+d x))}{a^2 d}+\frac {\cos (c+d x)}{b^2 d}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{b^4 d}-\frac {\cos ^3(c+d x)}{3 b^2 d}-\frac {a \cos (c+d x) \sin (c+d x)}{b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 d (a+b \sin (c+d x))}-\frac {\left (4 \left (a^2-b^2\right )^2\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^5 d} \\ & = \frac {a x}{b^3}+\frac {2 a \left (2 a^2-3 b^2\right ) x}{b^5}+\frac {2 \left (a^2-b^2\right )^{3/2} \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^5 d}-\frac {2 \left (a^2-b^2\right )^{3/2} \left (5 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^2 b^5 d}-\frac {\text {arctanh}(\cos (c+d x))}{a^2 d}+\frac {\cos (c+d x)}{b^2 d}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{b^4 d}-\frac {\cos ^3(c+d x)}{3 b^2 d}-\frac {a \cos (c+d x) \sin (c+d x)}{b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 d (a+b \sin (c+d x))} \\ \end{align*}
Time = 1.41 (sec) , antiderivative size = 207, normalized size of antiderivative = 0.78 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {12 a \left (4 a^2-5 b^2\right ) (c+d x)}{b^5}-\frac {24 \left (a^2-b^2\right )^{3/2} \left (4 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^2 b^5}+\frac {9 \left (4 a^2-3 b^2\right ) \cos (c+d x)}{b^4}-\frac {\cos (3 (c+d x))}{b^2}-\frac {12 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{a^2}+\frac {12 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )}{a^2}+\frac {12 \left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 (a+b \sin (c+d x))}-\frac {6 a \sin (2 (c+d x))}{b^3}}{12 d} \]
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Time = 1.54 (sec) , antiderivative size = 314, normalized size of antiderivative = 1.18
method | result | size |
derivativedivides | \(\frac {-\frac {4 \left (\frac {-\frac {b^{2} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}-\frac {a^{5} b}{2}+a^{3} b^{3}-\frac {a \,b^{5}}{2}}{\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {\left (4 a^{6}-7 a^{4} b^{2}+2 a^{2} b^{4}+b^{6}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}}\right )}{a^{2} b^{5}}+\frac {\frac {4 \left (\frac {\left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}}{2}+\left (\frac {3}{2} a^{2} b -\frac {3}{2} b^{3}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (3 a^{2} b -2 b^{3}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a \,b^{2}}{2}+\frac {3 a^{2} b}{2}-\frac {7 b^{3}}{6}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{3}}+2 a \left (4 a^{2}-5 b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{b^{5}}+\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{2}}}{d}\) | \(314\) |
default | \(\frac {-\frac {4 \left (\frac {-\frac {b^{2} \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}-\frac {a^{5} b}{2}+a^{3} b^{3}-\frac {a \,b^{5}}{2}}{\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {\left (4 a^{6}-7 a^{4} b^{2}+2 a^{2} b^{4}+b^{6}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}}\right )}{a^{2} b^{5}}+\frac {\frac {4 \left (\frac {\left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a \,b^{2}}{2}+\left (\frac {3}{2} a^{2} b -\frac {3}{2} b^{3}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (3 a^{2} b -2 b^{3}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a \,b^{2}}{2}+\frac {3 a^{2} b}{2}-\frac {7 b^{3}}{6}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{3}}+2 a \left (4 a^{2}-5 b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{b^{5}}+\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{2}}}{d}\) | \(314\) |
risch | \(\frac {4 a^{3} x}{b^{5}}-\frac {5 a x}{b^{3}}+\frac {4 i \sqrt {a^{2}-b^{2}}\, a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d \,b^{5}}+\frac {3 \,{\mathrm e}^{i \left (d x +c \right )} a^{2}}{2 d \,b^{4}}-\frac {9 \,{\mathrm e}^{i \left (d x +c \right )}}{8 b^{2} d}+\frac {3 \,{\mathrm e}^{-i \left (d x +c \right )} a^{2}}{2 d \,b^{4}}-\frac {9 \,{\mathrm e}^{-i \left (d x +c \right )}}{8 d \,b^{2}}+\frac {i a \,{\mathrm e}^{2 i \left (d x +c \right )}}{4 b^{3} d}+\frac {2 i \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \left (-i a \,{\mathrm e}^{i \left (d x +c \right )}+b \right )}{a \,b^{5} d \left (b \,{\mathrm e}^{2 i \left (d x +c \right )}-b +2 i a \,{\mathrm e}^{i \left (d x +c \right )}\right )}-\frac {i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d b \,a^{2}}+\frac {3 i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d \,b^{3}}-\frac {i a \,{\mathrm e}^{-2 i \left (d x +c \right )}}{4 b^{3} d}+\frac {i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d b \,a^{2}}-\frac {3 i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d \,b^{3}}-\frac {4 i \sqrt {a^{2}-b^{2}}\, a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d \,b^{5}}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{d \,a^{2}}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{d \,a^{2}}-\frac {\cos \left (3 d x +3 c \right )}{12 b^{2} d}\) | \(576\) |
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Time = 0.85 (sec) , antiderivative size = 698, normalized size of antiderivative = 2.62 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\left [\frac {4 \, a^{3} b^{3} \cos \left (d x + c\right )^{3} + 6 \, {\left (4 \, a^{6} - 5 \, a^{4} b^{2}\right )} d x - 3 \, {\left (4 \, a^{5} - 3 \, a^{3} b^{2} - a b^{4} + {\left (4 \, a^{4} b - 3 \, a^{2} b^{3} - b^{5}\right )} \sin \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}} \log \left (-\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} - 2 \, {\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) + 6 \, {\left (4 \, a^{5} b - 5 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right ) - 3 \, {\left (b^{6} \sin \left (d x + c\right ) + a b^{5}\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + 3 \, {\left (b^{6} \sin \left (d x + c\right ) + a b^{5}\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 2 \, {\left (a^{2} b^{4} \cos \left (d x + c\right )^{3} - 3 \, {\left (4 \, a^{5} b - 5 \, a^{3} b^{3}\right )} d x - 6 \, {\left (a^{4} b^{2} - a^{2} b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{6 \, {\left (a^{2} b^{6} d \sin \left (d x + c\right ) + a^{3} b^{5} d\right )}}, \frac {4 \, a^{3} b^{3} \cos \left (d x + c\right )^{3} + 6 \, {\left (4 \, a^{6} - 5 \, a^{4} b^{2}\right )} d x + 6 \, {\left (4 \, a^{5} - 3 \, a^{3} b^{2} - a b^{4} + {\left (4 \, a^{4} b - 3 \, a^{2} b^{3} - b^{5}\right )} \sin \left (d x + c\right )\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \sin \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) + 6 \, {\left (4 \, a^{5} b - 5 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right ) - 3 \, {\left (b^{6} \sin \left (d x + c\right ) + a b^{5}\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + 3 \, {\left (b^{6} \sin \left (d x + c\right ) + a b^{5}\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 2 \, {\left (a^{2} b^{4} \cos \left (d x + c\right )^{3} - 3 \, {\left (4 \, a^{5} b - 5 \, a^{3} b^{3}\right )} d x - 6 \, {\left (a^{4} b^{2} - a^{2} b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{6 \, {\left (a^{2} b^{6} d \sin \left (d x + c\right ) + a^{3} b^{5} d\right )}}\right ] \]
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\[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\int \frac {\cos ^{6}{\left (c + d x \right )} \csc {\left (c + d x \right )}}{\left (a + b \sin {\left (c + d x \right )}\right )^{2}}\, dx \]
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Exception generated. \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.34 (sec) , antiderivative size = 353, normalized size of antiderivative = 1.33 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {3 \, \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{2}} + \frac {3 \, {\left (4 \, a^{3} - 5 \, a b^{2}\right )} {\left (d x + c\right )}}{b^{5}} - \frac {6 \, {\left (4 \, a^{6} - 7 \, a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} a^{2} b^{5}} + \frac {2 \, {\left (3 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 9 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 9 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 18 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 12 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 3 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 9 \, a^{2} - 7 \, b^{2}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{3} b^{4}} + \frac {6 \, {\left (a^{4} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 2 \, a^{2} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a^{5} - 2 \, a^{3} b^{2} + a b^{4}\right )}}{{\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a\right )} a^{2} b^{4}}}{3 \, d} \]
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Time = 13.78 (sec) , antiderivative size = 5197, normalized size of antiderivative = 19.54 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Too large to display} \]
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